In this article, we will just ignore air resistance for the sake of simplicity. Projectile motion happens when you throw an object at a certain angle, and the object (we called the object "projectile") moves along a curved path under the affect of gravitational force. If the projectile is launched with an initial velocity V_{0} then in terms of vector it can be written as:

V_{0}=V_{0x}i + V_{0y}j

The components V_{0x} and V_{0y} can be found if we know the angle θ_{0} between V_{0} and the positive x direction:

V_{0x}=V_{0} cos θ_{0}

V_{0y}=V_{0} sin θ_{0}

On the direction of x-axis (horizonal direction), there's no acceleration, so a_{x}=0; meanwhile on vertical direction (y-axis) the acceleration a_{y} is always -g, because gravitational force is pointing downwards.

Since we ignore air resistance, we can say the velocity of horizonal component of the motion V_{x} is always V_{0} cos θ_{0}, which equals to V_{0x}. For vertical direction, V_{y} will equal to V_{0y} - gt, and that is equivalent to V_{0} sin θ_{0 }- gt.

**Subject :**Science**Topic :**Physics-
**Posted By :**Jason **Created on :**09-27-2012

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